To calculate the energy (E) of a blackbody:
\[ E = h \times f \]
Where:
Blackbody energy refers to the energy emitted by a perfect blackbody, an idealized physical body that absorbs all incident electromagnetic radiation and re-emits it in a characteristic spectrum that depends only on the body’s temperature. The concept of blackbody radiation is fundamental in the field of quantum mechanics and thermodynamics. The energy of the radiation emitted by a blackbody is quantized and can be calculated using Planck’s law, which relates the energy of the radiation to its frequency through Planck’s constant.
Let's assume the following value:
Using the formula:
\[ E = 6.62607015 \times 10^{-34} \times 5 \times 10^{14} = 3.313 \times 10^{-19} \text{ J} \]
The energy is approximately \(3.313 \times 10^{-19}\) J.
Let's assume the following value:
Using the formula:
\[ E = 6.62607015 \times 10^{-34} \times 1 \times 10^{15} = 6.626 \times 10^{-19} \text{ J} \]
The energy is approximately \(6.626 \times 10^{-19}\) J.