The formula to calculate the Electrostatic Potential (V) is:
\[ V = \frac{[Coulomb] \cdot p \cdot \cos(\theta)}{|r|^2} \]
Where:
Electrostatic Potential is the potential energy per unit charge at a point in an electric field, measured relative to a reference point.
Electric Dipole Moment is a measure of the separation of positive and negative electric charges within a system, used to describe the distribution of electric charge.
Angle between any Two Vectors is the measure of orientation between two vectors in three-dimensional space, used to calculate electrostatic forces and interactions.
Magnitude of Position Vector is the length of the position vector from the origin to a point in an electrostatic field.
Let's assume the following values:
Using the formula:
\[ V = \frac{8.9875 \times 10^9 \cdot 0.6 \cdot \cos(1.5533)}{1371^2} \]
Evaluating:
\[ V \approx 50.0695 \, \text{Volts} \]
The Electrostatic Potential is approximately 50.0695 Volts.
| Electric Dipole Moment (p) (Coulomb Meters) | Angle between any Two Vectors (θ) (radians) | Magnitude of Position Vector (|r|) (meters) | Electrostatic Potential (V) (Volts) |
|---|---|---|---|
| 0.5 | 1.5 | 1300 | 188.0919 |
| 0.5 | 1.5 | 1371 | 169.1149 |
| 0.5 | 1.5 | 1400 | 162.1813 |
| 0.5 | 1.5533 | 1300 | 46.5208 |
| 0.5 | 1.5533 | 1371 | 41.8272 |
| 0.5 | 1.5533 | 1400 | 40.1123 |
| 0.5 | 1.6 | 1300 | -77.6422 |
| 0.5 | 1.6 | 1371 | -69.8087 |
| 0.5 | 1.6 | 1400 | -66.9466 |
| 0.6 | 1.5 | 1300 | 225.7103 |
| 0.6 | 1.5 | 1371 | 202.9379 |
| 0.6 | 1.5 | 1400 | 194.6175 |
| 0.6 | 1.5533 | 1300 | 55.8249 |
| 0.6 | 1.5533 | 1371 | 50.1926 |
| 0.6 | 1.5533 | 1400 | 48.1348 |
| 0.6 | 1.6 | 1300 | -93.1707 |
| 0.6 | 1.6 | 1371 | -83.7705 |
| 0.6 | 1.6 | 1400 | -80.3359 |
| 0.7 | 1.5 | 1300 | 263.3287 |
| 0.7 | 1.5 | 1371 | 236.7609 |
| 0.7 | 1.5 | 1400 | 227.0538 |
| 0.7 | 1.5533 | 1300 | 65.1291 |
| 0.7 | 1.5533 | 1371 | 58.5581 |
| 0.7 | 1.5533 | 1400 | 56.1572 |
| 0.7 | 1.6 | 1300 | -108.6991 |
| 0.7 | 1.6 | 1371 | -97.7322 |
| 0.7 | 1.6 | 1400 | -93.7253 |