The formula to calculate the electrolysis voltage (V) is:
\[ V = \frac{\Delta G}{n \cdot F} \]
Where:
Let's say the Gibbs Free Energy Change (\( \Delta G \)) is 50000 J and the number of moles of electrons (\( n \)) is 2. Using the formula:
\[ V = \frac{50000}{2 \cdot 96485} \]
We get:
\[ V \approx \frac{50000}{192970} \approx 0.26 \]
So, the electrolysis voltage (\( V \)) is approximately 0.26 V.
Electrolysis voltage is the minimum voltage required to drive an electrochemical reaction through the process of electrolysis. During electrolysis, electrical energy is used to drive a non-spontaneous chemical reaction. The voltage required depends on the Gibbs Free Energy Change of the reaction, the number of moles of electrons involved, and Faraday’s Constant. This voltage is crucial in various industrial processes, such as the extraction of metals, electroplating, and the production of chemical compounds.
