The formula to calculate the energy stored in a capacitor is:
\[ U = \frac{1}{2} C V_{\text{capacitor}}^2 \]
Where:
Energy stored in a capacitor is the energy that is stored in a capacitor, which is a device that stores electric energy in an electric field.
Capacitance is the ability of a system to store electric charge, typically measured in farads, and is a crucial concept in electrostatics.
Voltage in a capacitor is the electric potential difference across the plates of a capacitor, measured in volts, and is a fundamental concept in electrostatics.
Let's assume the following values:
Using the formula:
\[ U = \frac{1}{2} \cdot 0.011 \cdot 27.3^2 = 4.099095 \text{ J} \]
The energy stored is 4.099095 Joules.
| Capacitance (F) | Voltage (V) | Energy Stored (J) |
|---|---|---|
| 0.01 | 20 | 2.000000 |
| 0.01 | 22 | 2.420000 |
| 0.01 | 24 | 2.880000 |
| 0.01 | 26 | 3.380000 |
| 0.01 | 28 | 3.920000 |
| 0.01 | 30 | 4.500000 |
| 0.012 | 20 | 2.400000 |
| 0.012 | 22 | 2.904000 |
| 0.012 | 24 | 3.456000 |
| 0.012 | 26 | 4.056000 |
| 0.012 | 28 | 4.704000 |
| 0.012 | 30 | 5.400000 |
| 0.014 | 20 | 2.800000 |
| 0.014 | 22 | 3.388000 |
| 0.014 | 24 | 4.032000 |
| 0.014 | 26 | 4.732000 |
| 0.014 | 28 | 5.488000 |
| 0.014 | 30 | 6.300000 |
| 0.016 | 20 | 3.200000 |
| 0.016 | 22 | 3.872000 |
| 0.016 | 24 | 4.608000 |
| 0.016 | 26 | 5.408000 |
| 0.016 | 28 | 6.272000 |
| 0.016 | 30 | 7.200000 |
| 0.018 | 20 | 3.600000 |
| 0.018 | 22 | 4.356000 |
| 0.018 | 24 | 5.184000 |
| 0.018 | 26 | 6.084000 |
| 0.018 | 28 | 7.056000 |
| 0.018 | 30 | 8.100000 |