The formula to calculate the Face Area of Tetrahedron (AFace) is:
\[ A_{Face} = 6 \cdot \sqrt{3} \cdot ri^2 \]
Where:
Face Area of Tetrahedron is the quantity of plane enclosed by any equilateral triangular face of the Tetrahedron.
Insphere Radius of Tetrahedron is the radius of the sphere that is contained by the Tetrahedron in such a way that all the faces just touch the sphere.
Let's assume the following value:
Using the formula:
\[ A_{Face} = 6 \cdot \sqrt{3} \cdot 2^2 \]
Evaluating:
\[ A_{Face} \approx 41.5692 \, \text{square meters} \]
The Face Area of Tetrahedron is approximately 41.5692 square meters.
| Insphere Radius (ri) (meters) | Face Area (AFace) (square meters) |
|---|---|
| 1.5 | 23.3827 |
| 2 | 41.5692 |
| 2.5 | 64.9519 |