The formula to calculate Heat Transfer is:
\[ Q = \left| m_c \cdot c_c \cdot (T_{ci} - T_{co}) \right| \]
Heat is the form of energy that is transferred between systems or objects with different temperatures (flowing from the high-temperature system to the low-temperature system). Mass of Cold Fluid is the mass of the cooler fluid in the heat exchanger. Specific Heat Capacity of Cold Fluid is a physical property of matter, defined as the amount of heat to be supplied to a unit mass of the cooler fluid to produce a unit change in its temperature. Inlet Temperature of Cold Fluid is the temperature at which the cold fluid enters the heat exchanger. Outlet Temperature of Cold Fluid is the temperature at which the cold fluid exits the heat exchanger.
Let's assume the following values:
Using the formula:
\[ Q = \left| 9 \cdot 350 \cdot (283 - 303) \right| \approx 63000 \, \text{Joules} \]
The Heat Transfer is approximately 63000 Joules.
Mass of Cold Fluid (kg) | Heat Transfer (Joules) |
---|---|
8 | 56,000.000000000000000 |
8.2 | 57,399.999999999992724 |
8.4 | 58,799.999999999992724 |
8.6 | 60,199.999999999985448 |
8.8 | 61,599.999999999985448 |
9 | 62,999.999999999970896 |
9.2 | 64,399.999999999970896 |
9.4 | 65,799.999999999970896 |
9.6 | 67,199.999999999970896 |
9.8 | 68,599.999999999956344 |
10 | 69,999.999999999956344 |