The formula to calculate the Minimum Number of Teeth on Wheel to Avoid Interference if Pinion and Wheel have Equal Teeth is:
\[ T = \frac{2 \cdot A_w}{\sqrt{1 + 3 \cdot \left( \sin(\Phi_{\text{gear}}) \right)^2} - 1} \]
Where:
The minimum number of teeth on wheel is the count of teeth on the wheel required to avoid interference when the pinion and wheel have equal teeth.
Let's assume the following values:
Using the formula:
\[ T = \frac{2 \cdot A_w}{\sqrt{1 + 3 \cdot \left( \sin(\Phi_{\text{gear}}) \right)^2} - 1} \]
Evaluating:
\[ T = \frac{2 \cdot 0.0245}{\sqrt{1 + 3 \cdot \left( \sin(0.55850536063808) \right)^2} - 1} \]
The Minimum Number of Teeth on Wheel is 0.137114214810417.
| Addendum of Wheel (m) | Pressure Angle (rad) | Minimum Number of Teeth on Wheel |
|---|---|---|
| 0.02 | 0.55850536063808 | 0.111929971274 |
| 0.022 | 0.55850536063808 | 0.123122968401 |
| 0.024 | 0.55850536063808 | 0.134315965529 |
| 0.026 | 0.55850536063808 | 0.145508962656 |
| 0.028 | 0.55850536063808 | 0.156701959783 |