The formula to calculate Molecular Formula (M.F) is:
\[ M.F = \frac{Mmolar}{EFM} \]
Where:
Molecular Formula is the expression of the number of atoms of each element in one molecule of a compound.
Molar Mass is the mass of a given substance divided by the amount of substance.
Mass of Empirical Formulas is the total mass of the simplest positive integer ratio of atoms present in a compound.
Let's assume the following values:
Using the formula:
\[ M.F = \frac{Mmolar}{EFM} \]
Evaluating:
\[ M.F = \frac{0.04401}{1.802E-05} \]
The Molecular Formula is 2442.28634850166.
| Molar Mass (Kilograms per Mole) | Mass of Empirical Formulas (Kilograms) | Molecular Formula |
|---|---|---|
| 0.04 | 1.7E-5 | 2,352.941176470588289 |
| 0.04 | 1.8E-5 | 2,222.222222222222172 |
| 0.04 | 1.9E-5 | 2,105.263157894736651 |
| 0.041 | 1.7E-5 | 2,411.764705882353155 |
| 0.041 | 1.8E-5 | 2,277.777777777777828 |
| 0.041 | 1.9E-5 | 2,157.894736842105431 |
| 0.042 | 1.7E-5 | 2,470.588235294118022 |
| 0.042 | 1.8E-5 | 2,333.333333333333485 |
| 0.042 | 1.9E-5 | 2,210.526315789473756 |
| 0.043 | 1.7E-5 | 2,529.411764705882433 |
| 0.043 | 1.8E-5 | 2,388.888888888889142 |
| 0.043 | 1.9E-5 | 2,263.157894736842081 |
| 0.044 | 1.7E-5 | 2,588.235294117647300 |
| 0.044 | 1.8E-5 | 2,444.444444444444798 |
| 0.044 | 1.9E-5 | 2,315.789473684210407 |
| 0.045 | 1.7E-5 | 2,647.058823529412166 |
| 0.045 | 1.8E-5 | 2,500.000000000000455 |
| 0.045 | 1.9E-5 | 2,368.421052631579187 |
| 0.046 | 1.7E-5 | 2,705.882352941177032 |
| 0.046 | 1.8E-5 | 2,555.555555555555657 |
| 0.046 | 1.9E-5 | 2,421.052631578947512 |
| 0.047 | 1.7E-5 | 2,764.705882352941444 |
| 0.047 | 1.8E-5 | 2,611.111111111111313 |
| 0.047 | 1.9E-5 | 2,473.684210526315837 |
| 0.048 | 1.7E-5 | 2,823.529411764706310 |
| 0.048 | 1.8E-5 | 2,666.666666666666970 |
| 0.048 | 1.9E-5 | 2,526.315789473684617 |
| 0.049 | 1.7E-5 | 2,882.352941176471177 |
| 0.049 | 1.8E-5 | 2,722.222222222222626 |
| 0.049 | 1.9E-5 | 2,578.947368421052943 |