The formula to calculate the Normal Force is:
\[ Fn = Fc \cdot \sin(\theta) + Pt \cdot \cos(\theta) \]
Normal Force is the force which is normal to the shear force.
Let's assume the following values:
Using the formula:
\[ Fn = 1200 \cdot \sin(0.5235987755982) + 25 \cdot \cos(0.5235987755982) = 621.650635094611 \text{ N} \]
| Centripetal Force (Fc) | Theta (θ) | Tangential Force (Pt) | Normal Force (Fn) |
|---|---|---|---|
| 1100 N | 0.5235987755982 rad | 25 N | 571.650635094518 N |
| 1150 N | 0.5235987755982 rad | 25 N | 596.650635094514 N |
| 1200 N | 0.5235987755982 rad | 25 N | 621.650635094509 N |
| 1250 N | 0.5235987755982 rad | 25 N | 646.650635094505 N |
| 1300 N | 0.5235987755982 rad | 25 N | 671.650635094501 N |