The formula to calculate Normality (N) is:
\[ N = \frac{Eq \, of \, Solute}{Ltr \, of \, Solution} \]
Where:
Normality is the weight of solute dissolved in a liter of solution.
Equivalent of Solute is the amount of solute in the solution.
Liters of Solution is the amount of solution in liters.
Let's assume the following values:
Using the formula:
\[ N = \frac{Eq \, of \, Solute}{Ltr \, of \, Solution} \]
Evaluating:
\[ N = \frac{0.5}{0.005} \]
The Normality is 100 Mole per Cubic Meter.
| Equivalent of Solute (Equivalents) | Liters of Solution (Cubic Meters) | Normality (Mole per Cubic Meter) |
|---|---|---|
| 0.4 | 0.004 | 100.00 |
| 0.4 | 0.0045 | 88.89 |
| 0.4 | 0.005 | 80.00 |
| 0.4 | 0.0055 | 72.73 |
| 0.45 | 0.004 | 112.50 |
| 0.45 | 0.0045 | 100.00 |
| 0.45 | 0.005 | 90.00 |
| 0.45 | 0.0055 | 81.82 |
| 0.5 | 0.004 | 125.00 |
| 0.5 | 0.0045 | 111.11 |
| 0.5 | 0.005 | 100.00 |
| 0.5 | 0.0055 | 90.91 |
| 0.55 | 0.004 | 137.50 |
| 0.55 | 0.0045 | 122.22 |
| 0.55 | 0.005 | 110.00 |
| 0.55 | 0.0055 | 100.00 |