Parallel Wire Capacitance Calculator

Formula

To calculate the parallel wire capacitance:

\[ C = \left(\frac{120}{\sqrt{dc}}\right) \cdot \text{acosh}\left(\frac{s}{d}\right) \cdot 3.333 \cdot \sqrt{dc} \]

Where:

\(C\) is the Parallel Wire Capacitance (pF)
\(dc\) is the Relative Dielectric Constant
\(s\) is the Wire Separation (mm)
\(d\) is the Wire Diameter (mm)

What is Parallel Wire Capacitance?

A parallel wire capacitor is a type of electrical capacitor that is an electrical component that stores energy in the form of an electrostatic field. It consists of two parallel wires, often twisted around each other, which serve as its electrodes.

Example Calculation 1

Let's assume the following values:

Relative Dielectric Constant (\(dc\)) = 2.2
Wire Separation (\(s\)) = 10 mm
Wire Diameter (\(d\)) = 2 mm

Using the formula:

\[ C = \left(\frac{120}{\sqrt{2.2}}\right) \cdot \text{acosh}\left(\frac{10}{2}\right) \cdot 3.333 \cdot \sqrt{2.2} \]

The Parallel Wire Capacitance is approximately 251.19 pF.

Example Calculation 2

Let's assume the following values:

Relative Dielectric Constant (\(dc\)) = 4.5
Wire Separation (\(s\)) = 15 mm
Wire Diameter (\(d\)) = 3 mm

Using the formula:

\[ C = \left(\frac{120}{\sqrt{4.5}}\right) \cdot \text{acosh}\left(\frac{15}{3}\right) \cdot 3.333 \cdot \sqrt{4.5} \]

The Parallel Wire Capacitance is approximately 151.42 pF.