The formula to calculate the Real Power in Single-Phase AC Circuits is:
P=V2⋅cos(Φ)R
Where:
Real Power is the average power in watts delivered to a load. It is the actual power dissipated by the load.
Let's assume the following values:
Using the formula:
P=1302⋅cos(0.5235987755982)60
Evaluating:
P=243.930488732617 W
The Real Power is 243.930488732617 W.
Voltage (V) | Phase Difference (rad) | Resistance (Ω) | Real Power (W) |
---|---|---|---|
120 | 0.5235987755982 | 60 | 207.846096908277 |
122 | 0.5235987755982 | 60 | 214.832035165472 |
124 | 0.5235987755982 | 60 | 221.933443476505 |
126 | 0.5235987755982 | 60 | 229.150321841376 |
128 | 0.5235987755982 | 60 | 236.482670260084 |
130 | 0.5235987755982 | 60 | 243.930488732631 |
132 | 0.5235987755982 | 60 | 251.493777259015 |
134 | 0.5235987755982 | 60 | 259.172535839238 |
136 | 0.5235987755982 | 60 | 266.966764473298 |
138 | 0.5235987755982 | 60 | 274.876463161197 |
140 | 0.5235987755982 | 60 | 282.901631902933 |