The formula to calculate the Real Power in Single-Phase AC Circuits is:
\[ P = \frac{V^2 \cdot \cos(\Phi)}{R} \]
Where:
Real Power is the average power in watts delivered to a load. It is the actual power dissipated by the load.
Let's assume the following values:
Using the formula:
\[ P = \frac{130^2 \cdot \cos(0.5235987755982)}{60} \]
Evaluating:
\[ P = 243.930488732617 \text{ W} \]
The Real Power is 243.930488732617 W.
| Voltage (V) | Phase Difference (rad) | Resistance (Ω) | Real Power (W) |
|---|---|---|---|
| 120 | 0.5235987755982 | 60 | 207.846096908277 |
| 122 | 0.5235987755982 | 60 | 214.832035165472 |
| 124 | 0.5235987755982 | 60 | 221.933443476505 |
| 126 | 0.5235987755982 | 60 | 229.150321841376 |
| 128 | 0.5235987755982 | 60 | 236.482670260084 |
| 130 | 0.5235987755982 | 60 | 243.930488732631 |
| 132 | 0.5235987755982 | 60 | 251.493777259015 |
| 134 | 0.5235987755982 | 60 | 259.172535839238 |
| 136 | 0.5235987755982 | 60 | 266.966764473298 |
| 138 | 0.5235987755982 | 60 | 274.876463161197 |
| 140 | 0.5235987755982 | 60 | 282.901631902933 |