The formula to calculate the Radial Heat Flowing through Cylinder is:
\[ Q = k \cdot 2 \cdot \pi \cdot \Delta T \cdot l \div \ln\left(\frac{r_{\text{outer}}}{r_{\text{inner}}}\right) \]
Heat is the form of energy that is transferred between systems or objects with different temperatures (flowing from the high-temperature system to the low-temperature system). Thermal Conductivity is the rate of heat passing through a specified material, expressed as the amount of heat flowing per unit time through a unit area with a temperature gradient of one degree per unit distance. Temperature Difference is the measure of the hotness or the coldness of an object. Length of Cylinder is the vertical height of the Cylinder. The Outer Radius of Cylinder is a straight line from the center to the Cylinder's base to the outer surface of the Cylinder. The Inner Radius of Cylinder is a straight line from the center to the Cylinder's base to the inner surface of the Cylinder.
Let's assume the following values:
Using the formula:
\[ Q = 10.18 \cdot 2 \cdot \pi \cdot 5.25 \cdot 6.21 \div \ln\left(\frac{7.51}{3.5}\right) = 2731.39904320942 \text{ J} \]
| Thermal Conductivity (k) | Temperature Difference (ΔT) | Length of Cylinder (l) | Outer Radius (router) | Inner Radius (rinner) | Heat Flow (Q) |
|---|---|---|---|---|---|
| 10 W/m·K | 5.25 K | 6.21 m | 7.51 m | 3.5 m | 2,683.103185863870 J |
| 10.5 W/m·K | 5.25 K | 6.21 m | 7.51 m | 3.5 m | 2,817.258345157064 J |
| 11 W/m·K | 5.25 K | 6.21 m | 7.51 m | 3.5 m | 2,951.413504450257 J |
| 11.5 W/m·K | 5.25 K | 6.21 m | 7.51 m | 3.5 m | 3,085.568663743451 J |
| 12 W/m·K | 5.25 K | 6.21 m | 7.51 m | 3.5 m | 3,219.723823036644 J |