The formula to calculate the Radiative Heat Transfer is:
\[ Q = \sigma \cdot SA_{Body} \cdot F \cdot (T_1^4 - T_2^4) \]
Heat is the form of energy that is transferred between systems or objects with different temperatures (flowing from the high-temperature system to the low-temperature system). Body Surface Area is the total surface area of the human body. Geometric View Factor (in radiative heat transfer) is the proportion of the radiation which leaves a surface that strikes another surface. Temperature of Surface 1 is the temperature of the 1st surface. Temperature of Surface 2 is the temperature of the 2nd surface.
Let's assume the following values:
Using the formula:
\[ Q = 5.670367E-8 \cdot 8.5 \cdot 0.1 \cdot (503^4 - 293^4) = 2730.11033998808 \]
| Body Surface Area (SABody) | Geometric View Factor (F) | Temperature of Surface 1 (T1) | Temperature of Surface 2 (T2) | Heat (Q) |
|---|---|---|---|---|
| 8 | 0.1 | 503 | 293 | 2,569.515614106429894 |
| 8.1 | 0.1 | 503 | 293 | 2,601.634559282760165 |
| 8.2 | 0.1 | 503 | 293 | 2,633.753504459090436 |
| 8.3 | 0.1 | 503 | 293 | 2,665.872449635420708 |
| 8.4 | 0.1 | 503 | 293 | 2,697.991394811750979 |
| 8.5 | 0.1 | 503 | 293 | 2,730.110339988081250 |
| 8.6 | 0.1 | 503 | 293 | 2,762.229285164411522 |
| 8.7 | 0.1 | 503 | 293 | 2,794.348230340741793 |
| 8.8 | 0.1 | 503 | 293 | 2,826.467175517072064 |
| 8.9 | 0.1 | 503 | 293 | 2,858.586120693402336 |
| 9 | 0.1 | 503 | 293 | 2,890.705065869732607 |