Rectangular Hollow Tube Weight Calculator

Formula

To calculate the Rectangular Hollow Tube Weight:

$W = (H \times W - (W - t) \times (H - t)) \times L \times D$

Where:

$W$ is the Rectangular Hollow Tube Weight (lbs)
$H$ is the Height of the Tube (inches)
$W$ is the Width of the Tube (inches)
$t$ is the Thickness of the Tube Wall (inches)
$L$ is the Length of the Tube (feet)
$D$ is the Density of the Tube (lbs/ft³)

What is the weight of a Rectangular Hollow Tube?

The weight of a hollowed-out tube is equal to the total weight of the rectangular tube minus the weight of the inside hollow portion of the tube (if it is solid).

Example Calculation 1

Let's assume the following values:

Height of the Tube ( $H$ ) = 10 inches
Width of the Tube ( $W$ ) = 5 inches
Thickness of the Tube Wall ( $t$ ) = 0.5 inches
Length of the Tube ( $L$ ) = 20 feet
Density of the Tube ( $D$ ) = 490 lbs/ft³

Using the formula:

$W = (10 \times 5 - (5 - 0.5) \times (10 - 0.5)) \times 20 \times 490$

$W = (50 - 4.5 \times 9.5) \times 20 \times 490$

$W = (50 - 42.75) \times 20 \times 490$

$W = 7.25 \times 20 \times 490 = 71050 \text{ lbs}$

The Rectangular Hollow Tube Weight is approximately 71,050 lbs.

Example Calculation 2

Let's assume the following values:

Height of the Tube ( $H$ ) = 8 inches
Width of the Tube ( $W$ ) = 4 inches
Thickness of the Tube Wall ( $t$ ) = 0.25 inches
Length of the Tube ( $L$ ) = 15 feet
Density of the Tube ( $D$ ) = 500 lbs/ft³

Using the formula:

$W = (8 \times 4 - (4 - 0.25) \times (8 - 0.25)) \times 15 \times 500$

$W = (32 - 3.75 \times 7.75) \times 15 \times 500$

$W = (32 - 29.0625) \times 15 \times 500$

$W = 2.9375 \times 15 \times 500 = 22031.25 \text{ lbs}$

The Rectangular Hollow Tube Weight is approximately 22,031.25 lbs.