Rectangular Hollow Tube Weight Calculator

Formula

To calculate the Rectangular Hollow Tube Weight:

\[ W = (H \times W - (W - t) \times (H - t)) \times L \times D \]

Where:

\(W\) is the Rectangular Hollow Tube Weight (lbs)
\(H\) is the Height of the Tube (inches)
\(W\) is the Width of the Tube (inches)
\(t\) is the Thickness of the Tube Wall (inches)
\(L\) is the Length of the Tube (feet)
\(D\) is the Density of the Tube (lbs/ft³)

What is the weight of a Rectangular Hollow Tube?

The weight of a hollowed-out tube is equal to the total weight of the rectangular tube minus the weight of the inside hollow portion of the tube (if it is solid).

Example Calculation 1

Let's assume the following values:

Height of the Tube (\(H\)) = 10 inches
Width of the Tube (\(W\)) = 5 inches
Thickness of the Tube Wall (\(t\)) = 0.5 inches
Length of the Tube (\(L\)) = 20 feet
Density of the Tube (\(D\)) = 490 lbs/ft³

Using the formula:

\[ W = (10 \times 5 - (5 - 0.5) \times (10 - 0.5)) \times 20 \times 490 \]

\[ W = (50 - 4.5 \times 9.5) \times 20 \times 490 \]

\[ W = (50 - 42.75) \times 20 \times 490 \]

\[ W = 7.25 \times 20 \times 490 = 71050 \text{ lbs} \]

The Rectangular Hollow Tube Weight is approximately 71,050 lbs.

Example Calculation 2

Let's assume the following values:

Height of the Tube (\(H\)) = 8 inches
Width of the Tube (\(W\)) = 4 inches
Thickness of the Tube Wall (\(t\)) = 0.25 inches
Length of the Tube (\(L\)) = 15 feet
Density of the Tube (\(D\)) = 500 lbs/ft³

Using the formula:

\[ W = (8 \times 4 - (4 - 0.25) \times (8 - 0.25)) \times 15 \times 500 \]

\[ W = (32 - 3.75 \times 7.75) \times 15 \times 500 \]

\[ W = (32 - 29.0625) \times 15 \times 500 \]

\[ W = 2.9375 \times 15 \times 500 = 22031.25 \text{ lbs} \]

The Rectangular Hollow Tube Weight is approximately 22,031.25 lbs.