The formula to calculate Shear Strain (γ) is:
\[ \gamma = \frac{t}{L_0} \]
Shear Strain is the ratio of the change in deformation to its original length perpendicular to the axes of the member due to shear stress. The tangential displacement is the displacement of the body caused due to the action of tangential force. The Original Length refers to the material's initial size or dimension before any external forces are applied.
Let's assume the following values:
Using the formula:
\[ \gamma = \frac{5.678}{5} \approx 1.1356 \]
The Shear Strain is approximately 1.1356.
| Tangential Displacement (Meter) | Original Length (Meter) | Shear Strain |
|---|---|---|
| 5.5 | 5 | 1.100000000000000 |
| 5.51 | 5 | 1.102000000000000 |
| 5.52 | 5 | 1.104000000000000 |
| 5.53 | 5 | 1.106000000000000 |
| 5.54 | 5 | 1.108000000000000 |
| 5.55 | 5 | 1.110000000000000 |
| 5.56 | 5 | 1.112000000000000 |
| 5.57 | 5 | 1.114000000000000 |
| 5.58 | 5 | 1.116000000000000 |
| 5.59 | 5 | 1.118000000000000 |
| 5.6 | 5 | 1.120000000000000 |
| 5.61 | 5 | 1.121999999999999 |
| 5.62 | 5 | 1.123999999999999 |
| 5.63 | 5 | 1.125999999999999 |
| 5.64 | 5 | 1.127999999999999 |
| 5.65 | 5 | 1.129999999999999 |
| 5.66 | 5 | 1.131999999999999 |
| 5.67 | 5 | 1.133999999999999 |
| 5.68 | 5 | 1.135999999999999 |
| 5.69 | 5 | 1.137999999999999 |
| 5.7 | 5 | 1.139999999999999 |
| 5.71 | 5 | 1.141999999999999 |
| 5.72 | 5 | 1.143999999999999 |
| 5.73 | 5 | 1.145999999999999 |
| 5.74 | 5 | 1.147999999999999 |
| 5.75 | 5 | 1.149999999999999 |
| 5.76 | 5 | 1.151999999999999 |
| 5.77 | 5 | 1.153999999999999 |
| 5.78 | 5 | 1.155999999999999 |
| 5.79 | 5 | 1.157999999999999 |
| 5.8 | 5 | 1.159999999999999 |