The formula to calculate the Shunt Field Copper Loss is:
\[ P_{cu} = I_{sh}^2 \cdot R_{sh} \]
Copper loss refers to energy lost in the form of heat due to the resistance of the copper wire in an electrical device or system. Shunt field current is the current which flows through the shunt field windings. Shunt field resistance refers to the electrical resistance of the field winding in a shunt-wound DC motor or generator.
Let's assume the following values:
Using the formula:
\[ P_{cu} = 0.75^2 \cdot 185 = 104.0625 \text{ W} \]
| Shunt Field Current (Ish) | Shunt Field Resistance (Rsh) | Copper Loss (Pcu) |
|---|---|---|
| 0.7 A | 185 Ω | 90.6500 W |
| 0.71 A | 185 Ω | 93.2585 W |
| 0.72 A | 185 Ω | 95.9040 W |
| 0.73 A | 185 Ω | 98.5865 W |
| 0.74 A | 185 Ω | 101.3060 W |
| 0.75 A | 185 Ω | 104.0625 W |
| 0.76 A | 185 Ω | 106.8560 W |
| 0.77 A | 185 Ω | 109.6865 W |
| 0.78 A | 185 Ω | 112.5540 W |
| 0.79 A | 185 Ω | 115.4585 W |
| 0.8 A | 185 Ω | 118.4000 W |