The formula to calculate Kinetic Energy (KE) is:
\[ KE = \frac{I \cdot α_A^2}{2} \]
Where:
Kinetic Energy is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.
Equivalent Mass MOI of Geared System with Shaft A and B, is a quantity that determines the torque needed for a desired angular acceleration about a rotational axis.
Angular Acceleration of Shaft A is also known as rotational acceleration. It is a quantitative expression of the change in angular velocity per unit time.
Let's assume the following values:
Using the formula:
\[ KE = \frac{I \cdot α_A^2}{2} \]
Evaluating:
\[ KE = \frac{50 \cdot 25^2}{2} \]
The Kinetic Energy is 15625 J.
| Equivalent Mass MOI (I) | Angular Acceleration (αA) | Kinetic Energy (KE) |
|---|---|---|
| 40 | 20 | 8,000.000000000000000 |
| 40 | 22 | 9,680.000000000000000 |
| 40 | 24 | 11,520.000000000000000 |
| 40 | 26 | 13,520.000000000000000 |
| 40 | 28 | 15,680.000000000000000 |
| 40 | 30 | 18,000.000000000000000 |
| 45 | 20 | 9,000.000000000000000 |
| 45 | 22 | 10,890.000000000000000 |
| 45 | 24 | 12,960.000000000000000 |
| 45 | 26 | 15,210.000000000000000 |
| 45 | 28 | 17,640.000000000000000 |
| 45 | 30 | 20,250.000000000000000 |
| 50 | 20 | 10,000.000000000000000 |
| 50 | 22 | 12,100.000000000000000 |
| 50 | 24 | 14,400.000000000000000 |
| 50 | 26 | 16,900.000000000000000 |
| 50 | 28 | 19,600.000000000000000 |
| 50 | 30 | 22,500.000000000000000 |
| 55 | 20 | 11,000.000000000000000 |
| 55 | 22 | 13,310.000000000000000 |
| 55 | 24 | 15,840.000000000000000 |
| 55 | 26 | 18,590.000000000000000 |
| 55 | 28 | 21,560.000000000000000 |
| 55 | 30 | 24,750.000000000000000 |
| 60 | 20 | 12,000.000000000000000 |
| 60 | 22 | 14,520.000000000000000 |
| 60 | 24 | 17,280.000000000000000 |
| 60 | 26 | 20,280.000000000000000 |
| 60 | 28 | 23,520.000000000000000 |
| 60 | 30 | 27,000.000000000000000 |