The formula to calculate the Volume of a Right Square Pyramid given the Slant Height is:
\[ V = \frac{le(Base)^2 \cdot \sqrt{hslant^2 - \frac{le(Base)^2}{4}}}{3} \]
The Volume of a Right Square Pyramid is the total quantity of three-dimensional space enclosed by the surface of the pyramid. The Edge Length of the Base is the length of the straight line connecting any two adjacent vertices of the base. The Slant Height is the length measured along the lateral face from the base to the apex along the center of the face.
Let's assume the following values:
Using the formula:
\[ V = \frac{10^2 \cdot \sqrt{16^2 - \frac{10^2}{4}}}{3} = 506.622805119022 \]
The Volume of the Right Square Pyramid is 506.622805119022 cubic meters.
| Edge Length of Base (meters) | Slant Height (meters) | Volume (cubic meters) |
|---|---|---|
| 9 | 16 | 414.562118385170379 |
| 9.5 | 16 | 459.633069517142133 |
| 10 | 16 | 506.622805119022132 |
| 10.5 | 16 | 555.444975757050202 |
| 11 | 16 | 606.007494453107711 |