The formula to calculate Bond Order (B.O) is:
\[ B.O = \frac{1}{2} \left( B_{e^{-}} - A.B_{e^{-}} \right) \]
Where:
Bond Order is the number of chemical bonds present between a pair of atoms.
The Number of Bonding Electrons is the total number of electrons that can participate in forming chemical bonds with other atoms.
The number of Antibonding Electrons is the number of electrons which weakens the bond between two atoms and helps to raise the energy of the molecule relative to the separated atoms.
Let's assume the following values:
Using the formula:
\[ B.O = \frac{1}{2} \left( B_{e^{-}} - A.B_{e^{-}} \right) \]
Evaluating:
\[ B.O = \frac{1}{2} \left( 8 - 4 \right) \]
The Bond Order is 2.
| Number of Bonding Electrons | Number of Antibonding Electrons | Bond Order |
|---|---|---|
| 6 | 2 | 2.000000000000000 |
| 6 | 3 | 1.500000000000000 |
| 6 | 4 | 1.000000000000000 |
| 6 | 5 | 0.500000000000000 |
| 6 | 6 | 0.000000000000000 |
| 7 | 2 | 2.500000000000000 |
| 7 | 3 | 2.000000000000000 |
| 7 | 4 | 1.500000000000000 |
| 7 | 5 | 1.000000000000000 |
| 7 | 6 | 0.500000000000000 |
| 8 | 2 | 3.000000000000000 |
| 8 | 3 | 2.500000000000000 |
| 8 | 4 | 2.000000000000000 |
| 8 | 5 | 1.500000000000000 |
| 8 | 6 | 1.000000000000000 |
| 9 | 2 | 3.500000000000000 |
| 9 | 3 | 3.000000000000000 |
| 9 | 4 | 2.500000000000000 |
| 9 | 5 | 2.000000000000000 |
| 9 | 6 | 1.500000000000000 |
| 10 | 2 | 4.000000000000000 |
| 10 | 3 | 3.500000000000000 |
| 10 | 4 | 3.000000000000000 |
| 10 | 5 | 2.500000000000000 |
| 10 | 6 | 2.000000000000000 |