The formula to calculate the current density given conductivity and electric field is:
\[ J = \sigma \cdot E \]
Where:
Electric current density is the amount of electric current per unit area of a given cross-section, typically measured in amperes per square meter.
Conductivity is the ability of a material to conduct electricity, measured by the flow of electric current through it with minimal resistance.
Electric field is the force per unit charge at a given point in space, created by the presence of electric charges or changing magnetic fields.
Let's assume the following values:
Using the formula:
\[ J = 1667 \cdot 60000 = 100020000 \, \text{A/m²} \]
The current density is approximately 100020000 A/m².
| Conductivity (S/m) | Electric Field (V/m) | Current Density (A/m²) |
|---|---|---|
| 1000 | 50000 | 50,000,000.00 |
| 1000 | 55000 | 55,000,000.00 |
| 1000 | 60000 | 60,000,000.00 |
| 1000 | 65000 | 65,000,000.00 |
| 1000 | 70000 | 70,000,000.00 |
| 1200 | 50000 | 60,000,000.00 |
| 1200 | 55000 | 66,000,000.00 |
| 1200 | 60000 | 72,000,000.00 |
| 1200 | 65000 | 78,000,000.00 |
| 1200 | 70000 | 84,000,000.00 |
| 1400 | 50000 | 70,000,000.00 |
| 1400 | 55000 | 77,000,000.00 |
| 1400 | 60000 | 84,000,000.00 |
| 1400 | 65000 | 91,000,000.00 |
| 1400 | 70000 | 98,000,000.00 |
| 1600 | 50000 | 80,000,000.00 |
| 1600 | 55000 | 88,000,000.00 |
| 1600 | 60000 | 96,000,000.00 |
| 1600 | 65000 | 104,000,000.00 |
| 1600 | 70000 | 112,000,000.00 |
| 1800 | 50000 | 90,000,000.00 |
| 1800 | 55000 | 99,000,000.00 |
| 1800 | 60000 | 108,000,000.00 |
| 1800 | 65000 | 117,000,000.00 |
| 1800 | 70000 | 126,000,000.00 |
| 2000 | 50000 | 100,000,000.00 |
| 2000 | 55000 | 110,000,000.00 |
| 2000 | 60000 | 120,000,000.00 |
| 2000 | 65000 | 130,000,000.00 |
| 2000 | 70000 | 140,000,000.00 |