The formula to calculate the Eccentricity of a Hyperbola given its Linear Eccentricity and Semi Transverse Axis is:
\[ e = \frac{c}{a} \]
The Eccentricity of a Hyperbola is the ratio of distances of any point on the Hyperbola from the focus and the directrix, or it is the ratio of the linear eccentricity and the semi transverse axis of the Hyperbola. The Linear Eccentricity of a Hyperbola is half of the distance between the foci of the Hyperbola. The Semi Transverse Axis of a Hyperbola is half of the distance between the vertices of the Hyperbola.
Let's assume the following values:
Using the formula:
\[ e = \frac{13}{5} = 2.6 \text{ Meter} \]
The Eccentricity of the Hyperbola is 2.6 Meter.
| Linear Eccentricity (Meter) | Semi Transverse Axis (Meter) | Eccentricity (Meter) |
|---|---|---|
| 12 | 5 | 2.400000000000000 |
| 12.1 | 5 | 2.420000000000000 |
| 12.2 | 5 | 2.440000000000000 |
| 12.3 | 5 | 2.460000000000000 |
| 12.4 | 5 | 2.480000000000000 |
| 12.5 | 5 | 2.500000000000000 |
| 12.6 | 5 | 2.520000000000000 |
| 12.7 | 5 | 2.540000000000000 |
| 12.8 | 5 | 2.560000000000000 |
| 12.9 | 5 | 2.579999999999999 |
| 13 | 5 | 2.599999999999999 |
| 13.1 | 5 | 2.619999999999999 |
| 13.2 | 5 | 2.639999999999999 |
| 13.3 | 5 | 2.659999999999999 |
| 13.4 | 5 | 2.679999999999999 |
| 13.5 | 5 | 2.699999999999999 |
| 13.6 | 5 | 2.719999999999999 |
| 13.7 | 5 | 2.739999999999999 |
| 13.8 | 5 | 2.759999999999999 |
| 13.9 | 5 | 2.779999999999998 |
| 14 | 5 | 2.799999999999998 |