The formula to calculate Gear Efficiency (η) is:
\[ \eta = \frac{P_{\text{out}}}{P_{\text{in}}} \]
Where:
Gear Efficiency is simply the ratio of output shaft power to the input shaft power.
Output Power is the power supplied by the electrical machine to the load connected across it.
Input Power is the power, which is required by the appliance at its input i.e., from the plug point.
Let's assume the following values:
Using the formula:
\[ \eta = \frac{P_{\text{out}}}{P_{\text{in}}} \]
Evaluating:
\[ \eta = \frac{41}{46} \]
The Efficiency is 0.8913.
| Output Power (Pout, Watts) | Input Power (Pin, Watts) | Efficiency (η) |
|---|---|---|
| 40 | 45 | 0.8889 |
| 40 | 47 | 0.8511 |
| 40 | 49 | 0.8163 |
| 40 | 51 | 0.7843 |
| 40 | 53 | 0.7547 |
| 40 | 55 | 0.7273 |
| 42 | 45 | 0.9333 |
| 42 | 47 | 0.8936 |
| 42 | 49 | 0.8571 |
| 42 | 51 | 0.8235 |
| 42 | 53 | 0.7925 |
| 42 | 55 | 0.7636 |
| 44 | 45 | 0.9778 |
| 44 | 47 | 0.9362 |
| 44 | 49 | 0.8980 |
| 44 | 51 | 0.8627 |
| 44 | 53 | 0.8302 |
| 44 | 55 | 0.8000 |
| 46 | 45 | 1.0222 |
| 46 | 47 | 0.9787 |
| 46 | 49 | 0.9388 |
| 46 | 51 | 0.9020 |
| 46 | 53 | 0.8679 |
| 46 | 55 | 0.8364 |
| 48 | 45 | 1.0667 |
| 48 | 47 | 1.0213 |
| 48 | 49 | 0.9796 |
| 48 | 51 | 0.9412 |
| 48 | 53 | 0.9057 |
| 48 | 55 | 0.8727 |
| 50 | 45 | 1.1111 |
| 50 | 47 | 1.0638 |
| 50 | 49 | 1.0204 |
| 50 | 51 | 0.9804 |
| 50 | 53 | 0.9434 |
| 50 | 55 | 0.9091 |