The formula to calculate the Volume (V) of a Cuboid given the Length (l), Width (w), and Height (h) is:
\[ V = l \cdot w \cdot h \]
Where:
The Volume of a Cuboid is the total quantity of three-dimensional space enclosed by the surface of a Cuboid.
The Length of a Cuboid is the measure of any one of the pair of parallel edges of the base which are longer than the remaining pair of parallel edges of the Cuboid.
The Width of a Cuboid is the measure of any one of the pair of parallel edges of the base which are smaller than the remaining pair of parallel edges of the Cuboid.
The Height of a Cuboid is the vertical distance measured from the base to the top of the Cuboid.
Let's assume the following values:
Using the formula:
\[ V = 12 \cdot 6 \cdot 8 \]
Evaluating:
\[ V = 576 \]
The Volume of the Cuboid is 576 cubic meters.
| Length (l) (m) | Width (w) (m) | Height (h) (m) | Volume (V) (m³) |
|---|---|---|---|
| 10 | 5 | 8 | 400.0000 |
| 10 | 5 | 9 | 450.0000 |
| 10 | 5 | 10 | 500.0000 |
| 10 | 6 | 8 | 480.0000 |
| 10 | 6 | 9 | 540.0000 |
| 10 | 6 | 10 | 600.0000 |
| 10 | 7 | 8 | 560.0000 |
| 10 | 7 | 9 | 630.0000 |
| 10 | 7 | 10 | 700.0000 |
| 12 | 5 | 8 | 480.0000 |
| 12 | 5 | 9 | 540.0000 |
| 12 | 5 | 10 | 600.0000 |
| 12 | 6 | 8 | 576.0000 |
| 12 | 6 | 9 | 648.0000 |
| 12 | 6 | 10 | 720.0000 |
| 12 | 7 | 8 | 672.0000 |
| 12 | 7 | 9 | 756.0000 |
| 12 | 7 | 10 | 840.0000 |
| 14 | 5 | 8 | 560.0000 |
| 14 | 5 | 9 | 630.0000 |
| 14 | 5 | 10 | 700.0000 |
| 14 | 6 | 8 | 672.0000 |
| 14 | 6 | 9 | 756.0000 |
| 14 | 6 | 10 | 840.0000 |
| 14 | 7 | 8 | 784.0000 |
| 14 | 7 | 9 | 882.0000 |
| 14 | 7 | 10 | 980.0000 |